According to the following reaction,how much energy is required to decompose 55.0 kg of Fe₃O₄? The molar mass of Fe₃O₄is 231.55 g/mol.
Fe₃O₄(s) → 3 Fe(s) + 2 O₂(g) ΔH°_rxn= +1118 kJ

Question

According to the following reaction,how much energy is required to decompose 55.0 kg of Fe₃O₄? The molar mass of Fe₃O₄is 231.55 g/mol. Fe₃O₄(s)→ 3 Fe(s)+ 2 O₂(g)ΔH°_rxn= +1118 kJ

Quizplus · Accepted Answer

To find the energy required, first convert 55.0 kg of Fe₃O₄ to moles: 55,000 g / 231.55 g/mol = 237.59 mol. Then, multiply the moles by the ΔH°rxn: 237.59 mol × 1118 kJ/mol = 2.66 × 10⁵ kJ.

According to the Following Reaction,how Much Energy Is Required to Decompose