Determine the electron geometry,molecular geometry and polarity around the O of CH₃OH . A)eg = trigonal bipyramidal,mg = trigonal planar,nonpolar B)eg = octahedral,mg = square planar,nonpolar C)eg = tetrahedral,mg = bent,polar D)eg = tetrahedral,mg = linear,nonpolar E)eg = linear,mg = linear,polar

Question

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The central atom in CH₃OH is O, which is surrounded by four regions of electron density. Therefore, the electron geometry is tetrahedral. However, there are two bonding pairs and two lone pairs, causing the molecular geometry to be bent. The molecule is polar because the two lone pairs on oxygen cause an asymmetrical arrangement of the atoms around the central atom.

Determine the Electron Geometry,molecular Geometry and Polarity Around the O