Determine the rate law and the value of k for the following reaction using the data provided.
2 N2O5(g) → 4 NO2(g) + O2(g) ![Determine the rate law and the value of k for the following reaction using the data provided. 2 N<sub>2</sub>O<sub>5</sub>(g) → 4 NO<sub>2</sub>(g) + O<sub>2</sub>(g) A) Rate = 5.6 × 10<sup>-2</sup> M<sup>-1</sup>s<sup>-1</sup>[N<sub>2</sub>O<sub>5</sub>]<sup>2</sup> B) Rate = 6.0 × 10<sup>-1</sup> M<sup>-2</sup>s<sup>-1</sup>[N<sub>2</sub>O<sub>5</sub>]<sup>3</sup> C) Rate = 1.6 × 10<sup>-3</sup> M<sup>1/2</sup>s<sup>-1</sup>[N<sub>2</sub>O<sub>5</sub>]<sup>1/2</sup> D) Rate = 1.7 × 10<sup>-2</sup> M<sup>-1/2</sup>s<sup>-1</sup>[N<sub>2</sub>O<sub>5</sub>]<sup>3/2</sup> E) Rate = 5.2 × 10⁻<sup>3</sup> s<sup>-1</sup>[N<sub>2</sub>O<sub>5</sub>]](https://d2lvgg3v3hfg70.cloudfront.net/TB6106/11ec739f_d0db_25ac_b38b_752b48617c7c_TB6106_00.jpg)
A) Rate = 5.6 × 10-2 M-1s-1[N2O5]2
B) Rate = 6.0 × 10-1 M-2s-1[N2O5]3
C) Rate = 1.6 × 10-3 M1/2s-1[N2O5]1/2
D) Rate = 1.7 × 10-2 M-1/2s-1[N2O5]3/2
E) Rate = 5.2 × 10⁻3 s-1[N2O5]
Correct Answer:
Verified
Q28: What data should be plotted to show
Q29: The first-order decomposition of cyclopropane has a
Q31: The half-life for the second-order decomposition of
Q33: Determine the rate law and the value
Q35: Which of the following represents the integrated
Q36: Which of the following represents the integrated
Q37: Which of the following represents the equation
Q39: Given the following rate law,how does the
Q40: Determine the rate law and the value
Q43: Derive an expression for a "1/3-life" for
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents