The equilibrium constant is given for two of the reactions below.Determine the value of the missing equilibrium constant. A(g) + 2 B(g) ⇌ AB₂(g) Kc = 59
AB₂(g) + B(g) ⇌ AB₃(g) K_c = ?
A(g) + 3 B(g) ⇌ AB₃(g) K_c = 478

Question

Quizplus · Accepted Answer

The equilibrium constant for the third reaction can be found by multiplying the equilibrium constants of the first two reactions because the third reaction is the sum of the first two. Given $K_c$ for the first reaction is 59 and for the third reaction is 478, we need to find $K_c$ for the second reaction such that $59 \times K_c = 478$. Solving for $K_c$ gives $K_c = \frac{478}{59} \approx 8.1$.

The Equilibrium Constant Is Given for Two of the Reactions