The reaction below has a K_p value of 41.What is the value of K_c for this reaction at 400 K?
N₂(g) + 3 H₂(g) ⇌ 2 NH₃(g)

Question

The reaction below has a K_p value of 41.What is the value of K_c for this reaction at 400 K? N₂(g)+ 3 H₂(g)⇌ 2 NH₃(g)

Quizplus · Accepted Answer

The relationship between Kp and Kc is Kp = Kc(RT)^Δn, where Δn is the change in the number of moles of gas in the reaction. In this case, Δn = 2 - (1 + 3) = -2, so Kp = Kc(RT)^-2. Substituting the given values, we get Kc = Kp(RT)^2 = 41(0.0821 * 400)^2 = 4.4 × 10^4.

The Reaction Below Has a Kp Value of 41

The Reaction Below Has a K_p Value of 41