What is the hydronium ion concentration of a 0.500 M acetic acid solution with Ka = 1.8 × 10-5?
The equation for the dissociation of acetic acid is:
CH3CO2H(aq) + H2O(l) ⇌ H3O+(aq) + CH3CO2-(aq)
A) 3.0 × 10-2 M
B) 4.2 × 10-2 M
C) 3.0 × 10-3 M
D) 4.2 × 10-3 M
Correct Answer:
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