What is the pH of a 0.500 M NH₃ solution that has K_b = 1.8 × 10^-5? The equation for the dissociation of NH₃ is:
NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH^-(aq)

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What is the pH of a 0.500 M NH₃ solution that has K_b = 1.8 × 10^-5? The equation for the dissociation of NH₃ is: NH₃(aq)+ H₂O(l)⇌ NH₄⁺(aq)+ OH^-(aq) A)2.22 B)2.52 C)11.47 D)11.48

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The Answer of What is the pH of a 0.500 M NH₃ solution that has K_b = 1.8 × 10^-5? The equation for the dissociation of NH₃ is: NH₃(aq)+ H₂O(l)⇌ NH₄⁺(aq)+ OH^-(aq) A)2.22 B)2.52 C)11.47 D)11.48

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