The base-dissociation constant of ethylamine (C₂H₅NH₂)is 6.4 × 10^-⁴ at 25.0°C.The [H⁺] in a 1.6 × 10^-² M solution of ethylamine is ________ M. A)3.5 × 10^-¹² B)2.9 × 10^-3 C)3.1 × 10^-¹² D)3.2 × 10^-3 E)11.46

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Quizplus · Accepted Answer

The base-dissociation constant (Kb) is used to find the concentration of OH⁻ in the solution. Using the formula Kb = [C2H5NH3⁺][OH⁻]/[C2H5NH2], we can find [OH⁻]. Then, using the relation Kw = [H⁺][OH⁻] where Kw = 1.0 × 10⁻¹⁴, we can find [H⁺]. The correct [H⁺] is 3.5 × 10⁻¹² M.

The Base-Dissociation Constant of Ethylamine (C2H5NH2)is 6

The Base-Dissociation Constant of Ethylamine (C₂H₅NH₂)is 6