A jet plane is launched from a catapult on an aircraft carrier.In 2.0 s it reaches a speed of 42 m/s at the end of the catapult.Assuming the acceleration is constant,how far did it travel during those 2.0 s?
A)16 m
B)24 m
C)42 m
D)84 m

Question

Quizplus · Accepted Answer

The distance traveled can be calculated using the formula: distance = 0.5 * acceleration * time^2. First, find the acceleration: acceleration = (final velocity - initial velocity) / time = 42 m/s / 2 s = 21 m/s². Then, distance = 0.5 * 21 m/s² * (2 s)^2 = 42 m.

A Jet Plane Is Launched from a Catapult on an Aircraft