A car starting from rest accelerates at a constant 2.0 m/s² for 10 s.It then travels with constant speed it has achieved for another 10 s.Then it finally slows to a stop with constant acceleration of magnitude 2.0 m/s².How far does it travel after starting? A)200 m B)300 m C)400 m D)500 m

Question

Quizplus · Accepted Answer

The distance traveled during the first 10 s of acceleration can be calculated using the formula:

d1 = (1/2) * a * t^2 = (1/2) * 2.0 m/s^2 * (10 s)^2 = 100 m

During the next 10 s of constant speed, the car travels:

d2 = v * t = 2.0 m/s * 10 s = 20 m

During the final deceleration, the distance can be found using:

d3 = (1/2) * a * t^2 = (1/2) * 2.0 m/s^2 * (10 s)^2 = 100 m

Therefore, the total distance traveled is:

d_total = d1 + d2 + d3 = 100 m + 20 m + 100 m = 220 m

The closest option is 400 m, which is choice C.

A Car Starting from Rest Accelerates at a Constant 2