A car increases its forward velocity uniformly from 40 m/s to 80 m/s while traveling a distance of 200 m.What is its acceleration during this time? A)8.0 m/s² B)9.6 m/s² C)12 m/s² D)24 m/s²

Question

Quizplus · Accepted Answer

We can use the following kinematic equation to find the acceleration of the car:

v^2 = u^2 + 2as

where:
v = final velocity = 80 m/s
u = initial velocity = 40 m/s
s = displacement = 200 m
a = acceleration (what we're solving for)

Plugging in the values we get:

80^2 = 40^2 + 2a(200)
6400 = 1600 + 400a
400a = 4800
a = 12 m/s^2

Therefore, the acceleration of the car during this time is 12 m/s^2. The answer is (C).

A Car Increases Its Forward Velocity Uniformly from 40 M/s