When Jeff ran up a hill at 7.0 m/s,the horizontal component of his velocity vector was 5.1 m/s.What was the vertical component of Jeff's velocity?
A)4.8 m/s
B)4.3 m/s
C)3.8 m/s
D)3.4 m/s

Question

Quizplus · Accepted Answer

We can use the Pythagorean theorem to find the vertical component of Jeff's velocity. 
Let V be the vertical component of velocity. 
Then, 
(V)^2 + (5.1 m/s)^2 = (7.0 m/s)^2 
(V)^2 = (7.0 m/s)^2 - (5.1 m/s)^2 
(V)^2 = 24.19 m/s 
V = sqrt(24.19 m/s) 
V = 4.8 m/s 
Therefore, the vertical component of Jeff's velocity was 4.8 m/s.

When Jeff Ran Up a Hill at 7