An athlete competing in the long jump leaves the ground with a speed of 9.14 m/s at an angle of 35° above the horizontal.How long does the athlete stay in the air,assuming no significant air resistance?
A)0.50 s
B)0.88 s
C)1.1 s
D)2.5 s
E)0.54 s

Question

Quizplus · Accepted Answer

The time of flight in projectile motion is given by the formula $T = \frac{2u\sin\theta}{g}$, where $u$ is the initial velocity, $\theta$ is the launch angle, and $g$ is the acceleration due to gravity (approximately $9.8 \, \text{m/s}^2$). Plugging in the given values: $T = \frac{2 \times 9.14 \times \sin(35^\circ)}{9.8}$, we find that the time of flight is approximately 1.1 seconds.

An Athlete Competing in the Long Jump Leaves the Ground