A 250-kg motorcycle goes around an unbanked turn of radius 13.7 m at a steady 96.5 km/h.What is the magnitude of the net force on the motorcycle? A)719 N B)2.95 × 10³ N C)1.31 × 10⁴ N D)4.31 × 10⁴ N

Question

Quizplus · Accepted Answer

First, we need to convert the velocity to m/s: 
96.5 km/h = 26.8 m/s

Next, we can use the formula for centripetal force: 
F = mv²/r

F = (250 kg)(26.8 m/s)²/13.7 m

F = 1.31 × 10¹⁴ N

Therefore, the magnitude of the net force on the motorcycle is 1.31 × 10¹⁴ N, which is approximately equal to 1.31 × 10¹⁴ N. The correct choice is C, which is the only option close to this value.

A 250-Kg Motorcycle Goes Around an Unbanked Turn of Radius