Pulling out of a dive,the pilot of an airplane guides his plane into a vertical circle with a radius of 600 m.At the bottom of the dive,the speed of the airplane is 150 m/s.What is the apparent weight of the 70-kg pilot at that point?
A)3300 N
B)690 N
C)2600 N
D)490 N
E)1400 N

Question

Quizplus · Accepted Answer

The apparent weight of the pilot can be calculated using the formula for centripetal force, which is necessary to keep the pilot moving in a circle. This force is given by $F = \frac{mv^2}{r}$, where $m$ is the mass, $v$ is the velocity, and $r$ is the radius of the circle. At the bottom of the dive, the centripetal force acts upwards, adding to the normal force (the pilot's weight) to give the apparent weight. The pilot's actual weight is $mg = 70 \times 9.8 = 686$ N (approximately 690 N). The centripetal force is $\frac{70 \times 150^2}{600} = 2625$ N. The apparent weight is the sum of the actual weight and the centripetal force: $686 + 2625 = 3311$ N, which is approximately 3300 N.

Pulling Out of a Dive,the Pilot of an Airplane Guides