Three cars (car L,car M,and car N)are moving with the same speed and slam on their brakes.The most massive car is car L,and the least massive is car N.If the tires of all three cars have identical coefficients of kinetic friction with the road surface,for which car is the amount of work done by friction in stopping it the greatest?

Question

Quizplus · Accepted Answer

The amount of work done by friction in stopping a moving object is given by the equation: W = F*d, where W is the work done, F is the force of friction, and d is the distance over which the force is applied. Since all three cars have the same speed and the same coefficient of kinetic friction, the force of friction acting on each car is proportional to its mass. Therefore, car L will experience the greatest force of friction and will be stopped over the shortest distance, resulting in the greatest amount of work done by friction. Therefore, choice B is the best answer.

Three Cars (Car L,car M,and Car N)are Moving with the Same