The drive chain in a bicycle is applying a torque of 0.850 N ∙ m to the wheel of the bicycle.You can treat the wheel as a thin uniform hoop (or ring)with a mass of 0.750 kg and a radius of 33.0 cm.What is the angular acceleration of the wheel? A)10.4 rad/s² B)20.8 rad/s² C)5.20 rad/s² D)3.43 rad/s² E)1.06 rad/s²

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Quizplus · Accepted Answer

The torque applied to the wheel is given by:$$	au = I \alpha$$where:$$	au$$ is the torque$$I$$ is the moment of inertia$$\alpha$$ is the angular accelerationThe moment of inertia of a thin uniform hoop is given by:$$I = MR^2$$where:$$M$$ is the mass$$R$$ is the radiusSubstituting the given values into the equations, we get:$$0.850 	ext{ N} \cdot 	ext{m} = (0.750 	ext{ kg})(0.330 	ext{ m})^2 \alpha$$$$\alpha = 10.4 	ext{ rad/s}^2$$Therefore, the correct answer is A.

The Drive Chain in a Bicycle Is Applying a Torque