An object is undergoing simple harmonic motion of amplitude 2.3 m.If the maximum velocity of the object is 10 m/s,what is the object's angular frequency?
A)4.3 rad/s
B)4.8 rad/s
C)3.5 rad/s
D)4.0 rad/s

Question

Quizplus · Accepted Answer

The maximum velocity $v_{max}$ in simple harmonic motion is given by $v_{max} = \omega A$, where $\omega$ is the angular frequency and $A$ is the amplitude. Rearranging for $\omega$, we get $\omega = \frac{v_{max}}{A} = \frac{10 \, \text{m/s}}{2.3 \, \text{m}} \approx 4.3 \, \text{rad/s}$.

An Object Is Undergoing Simple Harmonic Motion of Amplitude 2