A 3.42-kg stone hanging vertically from an ideal spring on the earth undergoes simple harmonic motion at a place where g = 9.80 m/s².If the force constant (spring constant)of the spring is 12 N/m. Find the period of oscillation of this setup on a planet where g = 1.60 m/s². A)3.35 s B)2.51 s C)4.36 s D)5.70 s

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Quizplus · Accepted Answer

The period of oscillation for a mass-spring system is given by T = 2π√(m/k), which is independent of gravity. Using m = 3.42 kg and k = 12 N/m, T = 2π√(3.42/12) ≈ 3.35 s.

A 342-Kg Stone Hanging Vertically from an Ideal Spring on the the Earth