A string of linear density 1.5 g/m is under a tension of 20 N.What should be its length if its fundamental resonance frequency is 220 Hz?
A)0.26 m
B)0.96 m
C)1.1 m
D)1.2 m

Question

Quizplus · Accepted Answer

The fundamental resonance frequency of a string is given by:f = (1/2L) * sqrt(T/m)where:f is the frequency in HzL is the length of the string in metersT is the tension in Newtonsm is the linear density in kg/mSolving for L, we get:L = (1/2f) * sqrt(T/m)Plugging in the given values, we get:L = (1/2 * 220 Hz) * sqrt(20 N / 0.0015 kg/m)L = 0.26 m

A String of Linear Density 1