The coefficient of linear expansion of copper is 17 × 10^-6 K^-1.A sheet of copper has a round hole with a radius of 3.0 m cut out of it.If the sheet is heated and undergoes a change in temperature of 80 K,what is the change in the radius of the hole? A)It decreases by 4.1 mm. B)It increases by 4.1 mm. C)It decreases by 8.2 mm. D)It increases by 8.2 mm. E)It does not change.

Question

Quizplus · Accepted Answer

The radius of the hole increases due to thermal expansion. The change in radius can be calculated using the formula Δr = α * r * ΔT, where Δr is the change in radius, α is the coefficient of linear expansion, r is the original radius, and ΔT is the change in temperature. Substituting the given values: Δr = 17 × 10^-6 * 3.0 * 80 = 4.08 × 10^-3 m or 4.1 mm.

The Coefficient of Linear Expansion of Copper Is 17 ×