An aluminum electric tea kettle with a mass of 500 g is heated with a 500-W heating coil.How long will it take to heat up 1.0 kg of water from 18°C to 98°C in the tea kettle? The specific heat of aluminum is 900 J/kg ∙ K and that of water is 4186 J/kg ∙ K.

Question

Quizplus · Accepted Answer

Firstly, we need to find the amount of heat required to increase the temperature of water from 18°C to 98°C.
Q = m*c*ΔT
where m is the mass of water, c is the specific heat, and ΔT is the change in temperature.
Q = 1000g * 4186 J/kg * (98°C - 18°C)
Q = 3,534,680 J

Now, we need to find the time required to generate this amount of heat.
P = Q/t
where P is the power of the heating coil and t is the time taken.
500 W = 3,534,680 J/t
t = 7,069.36 seconds or 117.82 minutes.

Therefore, the answer is C) 12 minutes.

An Aluminum Electric Tea Kettle with a Mass of 500