An oxygen molecule,O2,falls in a vacuum.From what height must it fall so that its translational kinetic energy at the bottom of its fall equals the average translational kinetic energy of an oxygen molecule at 920 K? The mass of one O2 molecule is 5.312 × 10-26 kg,and the Boltzmann constant is 1.38 × 10-23 J/K.Neglect air resistance and assume that g remains constant at 9.8 m/s2 throughout the fall of the molecule.
A) 49 km
B) 12 km
C) 24 km
D) 37 km
E) 5.2 km
Correct Answer:
Verified
Q57: A 5.3 L flask of ideal neon
Q58: A laboratory vacuum pump can reduce the
Q59: How many moles are there in 2.00
Q60: A balloon originally has a volume of
Q61: The molecular weight of nitrogen,N2,is 28 g/mol.What
Q63: What is the average translational kinetic energy
Q64: A 4.2-L flask of ideal neon gas
Q65: Dust particles in a grain elevator frequently
Q66: A sealed container holds 0.020 moles of
Q67: The rms speed of a certain sample
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents