An ideal Carnot engine extracts 529 J of heat from a high-temperature reservoir during each cycle,and rejects
Of heat to a low-temperature reservoir during the same cycle.What is the efficiency of the engine?
A)0.57
B)1.35
C)2.35
D)0.7

Question

An ideal Carnot engine extracts 529 J of heat from a high-temperature reservoir during each cycle,and rejects 
Of heat to a low-temperature reservoir during the same cycle.What is the efficiency of the engine?
A)0.57 
B)1.35 
C)2.35 
D)0.7

Quizplus · Accepted Answer

The efficiency of a Carnot engine is given by: 
Efficiency = (1- T_low/T_high)

where T_low and T_high are the temperatures of the low-temperature and high-temperature reservoirs, respectively.

In this case, we are given that the engine extracts 529 J of heat from the high-temperature reservoir and rejects 11ea6c4e_0053_4f2d_9875_0b77468b99f5_TB6214_11 J of heat to the low-temperature reservoir during each cycle. Thus, the net work done by the engine is:

W = Q_h - Q_l = 529 J - 11ea6c4e_0053_4f2d_9875_0b77468b99f5_TB6214_11 J = 418 J

We know that the efficiency is the ratio of the net work done to the heat absorbed from the high-temperature reservoir:

Efficiency = W/Q_h = 418 J / 529 J = 0.57

Therefore, the answer is A) 0.57.

An Ideal Carnot Engine Extracts 529 J of Heat from a High-Temperature