The zirconium nucleus contains 40 protons,and an electron is 1.0 nm from the nucleus.What is the electric force on the electron due to the nucleus? ( e = 1.60 × 10^-19 C,k = 1/4πε₀ = 9.0 × 10⁹ N ∙ m²/C²) A)2.9 nN B)1000 C C)3.7 nN D)6.8 nN E)9.2 nN

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The electric force can be calculated using Coulomb's law: F = k * |q1 * q2| / r^2. Here, q1 = 40e (charge of the nucleus), q2 = -e (charge of the electron), and r = 1.0 nm = 1.0 × 10^-9 m. Substituting the values, F = 9.0 × 10^9 * |40 * 1.60 × 10^-19 * 1.60 × 10^-19| / (1.0 × 10^-9)^2 = 9.2 nN.

The Zirconium Nucleus Contains 40 Protons,and an Electron Is 1