An ideal parallel-plate capacitor consists of two parallel plates of area A separated by a distance d.This capacitor is connected across a battery that maintains a constant potential difference between the plates.If the separation between the plates is now doubled,the magnitude of the charge on the plates will

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The charge on a parallel-plate capacitor is given by Q = CV, where C is the capacitance and V is the potential difference across the plates. The capacitance is given by C = εA/d, where ε is the permittivity, A is the area of the plates, and d is the separation between them. When the separation is doubled (i.e., d → 2d), the capacitance is halved (i.e., C → C/2). Since the potential difference V is held constant, the charge Q must also halve (i.e., Q → Q/2). Therefore, the correct choice is C, i.e., the charge will be cut in half.

An Ideal Parallel-Plate Capacitor Consists of Two Parallel Plates of Area