An ideal air-filled parallel-plate capacitor with horizontal plates has a plate separation of 5.0 cm.If the potential difference between the plates is 2000 V,with the top plate at the higher potential,what are the magnitude and direction of the electric field between the plates?

Question

Quizplus · Accepted Answer

The electric field (E) between the plates of a parallel-plate capacitor is given by E = V/d, where V is the potential difference and d is the separation between the plates. Here, E = 2000 V / 0.05 m = 40000 N/C. The direction is downward because the electric field points from the positive (higher potential) to the negative (lower potential) plate.

An Ideal Air-Filled Parallel-Plate Capacitor with Horizontal Plates Has a Plate