When a 4-μF capacitor has a potential drop of 20 V across its plates,how much electric potential energy is stored in this capacitor?

Question

Quizplus · Accepted Answer

The electric potential energy stored in a capacitor is given by the formula:

U = (1/2) * C * V^2

where U is the energy stored, C is the capacitance, and V is the potential difference across the capacitor.

Plugging in the given values, we get:

U = (1/2) * 4e-6 F * (20V)^2
  = 800e-6 J
  = 800 μJ

Therefore, the answer is D.

When a 4-μF Capacitor Has a Potential Drop of 20