What is the resistance of a 0.100-kW light bulb designed to be used in a 120-V circuit dc?
A)12.0 Ω
B)144 Ω
C)1.2 Ω
D)0.83 Ω

Question

Quizplus · Accepted Answer

The resistance can be calculated using the formula $P = \frac{V^2}{R}$, where $P$ is the power in watts, $V$ is the voltage in volts, and $R$ is the resistance in ohms. Rearranging the formula to solve for $R$ gives $R = \frac{V^2}{P}$. Substituting the given values ($P = 100$ watts, $V = 120$ volts) into the formula yields $R = \frac{120^2}{100} = 144$ ohms.

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