An electron moves with a speed of 5.0 × 10⁴ m/s perpendicular to a uniform magnetic field of magnitude 0.20 T.What is the magnitude of the magnetic force on the electron? (e = 1.60 × 10^-19C) A)4.4 × 10^-14 N B)1.6 × 10^-15 N C)5 × 10^-20 N D)2.6 × 10^-24 N

Question

Quizplus · Accepted Answer

The magnetic force on a charged particle moving perpendicular to a magnetic field is given by F = qvB. Substituting the given values: F = (1.60 × 10^-19 C)(5.0 × 10^4 m/s)(0.20 T) = 1.6 × 10^-15 N.

An Electron Moves with a Speed of 5