A coil with a self-inductance of 6.0 H is connected to a dc battery through a switch.As soon as the switch is closed,the rate of change of current is 2.0 A/s.What is the emf induced in this coil at this instant?
A)6.0 V
B)3.0 V
C)12 V
D)0.33 V
E)0.0 V

Question

Quizplus · Accepted Answer

The emf induced in the coil at any instant is given by the formula emf = -L*(di/dt), where L is the self-inductance of the coil and di/dt is the rate of change of current.

Substituting the given values, we have:

emf = -6.0 H * (2.0 A/s) = -12 V

Since the emf is induced in the opposite direction to the current, the negative sign indicates that the emf opposes the increase in current. Therefore, the magnitude of the emf is 12 V.

Hence, the correct answer is C) 12V

A Coil with a Self-Inductance of 6