A 10-Ω resistor is connected to a 120-V ac power supply.What is the peak current through the resistor?
A)12 A
B)17 A
C)0.083 A
D)0.12 A

Question

Quizplus · Accepted Answer

We can use Ohm's law for an AC circuit to find the peak current:

Vpeak = Ipeak * R

Rearranging the equation to solve for Ipeak:

Ipeak = Vpeak / R

The peak voltage for a 120V AC power supply is:

Vpeak = 120V * sqrt(2) = 169.7V

Substituting into the equation above:

Ipeak = 169.7V / 10Ω = 16.97A

Rounding to the nearest whole number, we get:

Ipeak = 17A

Therefore, the answer is B).

A 10-Ω Resistor Is Connected to a 120-V Ac Power