Jack and Mary view the same microorganism through the same compound microscope.Mary's near point distance,N_M,is twice as large as Jack's near point distance,N_J.If Mary sees the microorganism with magnification M_M,with what magnification does Jack see it? A)2 M_M B)M_M/2 C)4 M_M D)M_M/4 E)8 M_M

Question

Quizplus · Accepted Answer

The magnification of a compound microscope is equal to the product of the magnifying power of the objective lens and the eyepiece lens. Let the magnifying power of the objective lens be denoted by MO and the magnifying power of the eyepiece lens be denoted by ME. Then, the magnification of the microscope is MO x ME.
We can write MO x ME = MS1U1B1MS1U1B0 for Mary's viewing of the microorganism. Let J denote Jack's near point distance and MJ denote the magnifying power of the microscope for Jack. Then, we have MO x ME = MJ x (J/S1U1B0), where J/S1U1B0 is Jack's magnification due to his near point distance. We are given that Jack's near point distance is half of Mary's, so J = 2S1U1B0. Substituting this into the equation above, we get MO x ME = MJ x 2. Solving for MJ, we get MJ = (MO x ME)/2 = MS1U1B1MS1U1B0/2. Therefore, Jack sees the microorganism with a magnification of MS1U1B1MS1U1B0/2.

Jack and Mary View the Same Microorganism Through the Same