A single slit,1,400 nm wide,forms a diffraction pattern when illuminated by monochromatic light of 490-nm wavelength.What is the largest angle from the central maximum at which the intensity of the light is zero?
A)44°
B)41°
C)38°
D)35°
E)32°

Question

Quizplus · Accepted Answer

The largest angle from the central maximum at which the intensity of the light is zero is given by:sin θ = λ/wwhere λ is the wavelength of the light and w is the width of the slit.Plugging in the given values, we get:sin θ = (490 nm)/(1400 nm) = 0.35θ = sin^-1(0.35) = 20.7°The largest angle from the central maximum at which the intensity of the light is zero is therefore 20.7°.

A Single Slit,1,400 Nm Wide,forms a Diffraction Pattern When Illuminated