A round 0.85-mm-diameter hole is illuminated by infrared light of wavelength 2.5 μm What is the angle of the first dark fringe in the resulting pattern? A)0.21 degrees B)3.6 × 10^-3_degrees C)1.2 × 10^-2_degrees D)4.8 × 10^-2_degrees

Question

Quizplus · Accepted Answer

The angle of the first dark fringe in the resulting pattern can be found using the formula:

sin(theta) = 1.22(lambda)/D

where lambda is the wavelength of light, D is the diameter of the hole, and theta is the angle of the first dark fringe.

Substituting the values given, we get:

sin(theta) = 1.22(2.5 x 10^-6 m)/(0.85 x 10^-3 m)

sin(theta) = 0.0354

theta = sin^-1(0.0354)

theta = 0.21 degrees

Therefore, the answer is A) 0.21 degrees.

A Round 085-Mm-Diameter Hole Is Illuminated by Infrared Light of Wavelength 2