Each photon in a beam of light has an energy of 4.20 eV.What is the wavelength of this light? (c = 3.00 × 10⁸ m/s,h = 6.626 × 10^-34 J ∙ s,1 eV = 1.60 × 10^-19 J) A)321 nm B)103 nm C)296 nm D)412 nm E)420 nm

Question

Quizplus · Accepted Answer

We know that the energy of a photon is given by:
E = hc/λ
where h is Planck's constant, c is the speed of light, and λ is the wavelength of the light.
Rearranging this equation, we get:
λ = hc/E
Substituting the given values, we get:
λ = (6.626 × 10^-34 J ∙ s × 3.00 × 10^8 m/s) / (4.20 × 1.60 × 10^-19 J)
λ = 2.957 × 10^-7 m = 296 nm
Therefore, the correct answer is (C).

Each Photon in a Beam of Light Has an Energy