A metal has a work function of 4.50 eV.Find the maximum kinetic energy of the photoelectrons if light of wavelength 250 nm shines on the metal.(1 eV = 1.60 × 10^-19 J,c = 3.00 × 10⁸ m/s,h = 6.626 × 10^-34 J ∙ s) A)0.00 eV B)0.37 eV C)0.47 eV D)0.53 eV

Question

Quizplus · Accepted Answer

The energy of a photon of light can be calculated using the formula:

E = hc/λ

where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of light.

We can use this formula to calculate the energy of a photon of light with a wavelength of 250 nm:

E = (6.626 × 10^-34 J s) * (3.00 × 10^8 m/s) / (250 × 10^-9 m) = 7.95 × 10^-19 J

To calculate the maximum kinetic energy of the photoelectrons, we can use the formula:

KEmax = E - Φ

where KEmax is the maximum kinetic energy of the photoelectrons, E is the energy of the photon of light, and Φ is the work function of the metal.

Plugging in the values given in the question, we get:

KEmax = (7.95 × 10^-19 J) - (4.50 eV * 1.60 × 10^-19 J/eV) = 0.47 eV

Therefore, the maximum kinetic energy of the photoelectrons is 0.47 eV. The correct choice is C.

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