If an electron has the same de Broglie wavelength as the wavelength of a 390-nm photon in vacuum,what is the speed of the electron? (m_electron = 9.11 × 10^-31 kg,c = 3.0 × 10⁸ m/s,h = 6.626 × 10^-34 J ∙ s) A)1,900 m/s B)2,100 m/s C)1,700m/s D)1,500 m/s E)540 m/s

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Quizplus · Accepted Answer

The de Broglie wavelength λ is given by λ = h/p, where p is the momentum. For an electron, p = mv. Setting the de Broglie wavelength equal to the photon's wavelength (390 nm), we have h/(mv) = 390 nm. Solving for v gives v = h/(m * 390 nm). Substituting the given values, v ≈ 1,900 m/s.

If an Electron Has the Same De Broglie Wavelength as the Wavelength