The neutral deuterium atom,
H,has a mass of 2.014102 u;a neutral ordinary hydrogen atom has a mass of 1.007825 u;a neutron has a mass of 1.008665 u;and a proton has a mass of 1.007277 u.What is the binding energy of the deuterium nucleus? (1 u = 931.5 MeV/c²)

Question

The neutral deuterium atom, The neutral deuterium atom, H,has a mass of 2.014102 u;a neutral ordinary hydrogen atom has a mass of 1.007825 u;a neutron has a mass of 1.008665 u;and a proton has a mass of 1.007277 u.What is the binding energy of the deuterium nucleus? (1 u = 931.5 MeV/c<sup>2</sup>) A) 1.1 MeV B) 1.7 MeV C) 2.2 MeV D) 2.9 MeV E) 3.4 MeV

The neutral deuterium atom, H,has a mass of 2.014102 u;a neutral ordinary hydrogen atom has a mass of 1.007825 u;a neutron has a mass of 1.008665 u;and a proton has a mass of 1.007277 u.What is the binding energy of the deuterium nucleus? (1 u = 931.5 MeV/c<sup>2</sup>) A) 1.1 MeV B) 1.7 MeV C) 2.2 MeV D) 2.9 MeV E) 3.4 MeV

H,has a mass of 2.014102 u;a neutral ordinary hydrogen atom has a mass of 1.007825 u;a neutron has a mass of 1.008665 u;and a proton has a mass of 1.007277 u.What is the binding energy of the deuterium nucleus? (1 u = 931.5 MeV/c²)

Quizplus · Accepted Answer

The binding energy of a nucleus is given by the difference between its mass and the sum of the masses of its constituent particles. In this case:

binding energy = (mass of deuterium nucleus) - (mass of proton + mass of neutron)
binding energy = (2.014102 u) - (1.007277 u + 1.008665 u)
binding energy = 0.99816 u

Converting to MeV using the given conversion factor:

binding energy = 0.99816 u * 931.5 MeV/c^2/u
binding energy = 929.57 MeV

Therefore, the binding energy of the deuterium nucleus is 2.2 MeV.

The Neutral Deuterium Atom