Consider the following class definitions:
class bClass
{
public:
$\quad$void setX(int);
$\quad$void print()const;
private:
$\quad$int x;
};
Class dClass: public bClass
{
Public:
$\quad$void setXY(int,int);
$\quad$void print()const;
private:
$\quad$Int y;
};
Which of the following statements correctly redefines the member function print of bClass?
A) void dClass::print() const
{
$\quad$dClass:print();
$\quad$cout

Question

Consider the following class definitions: 
class bClass
{
public:
$\quad$void setX(int);
$\quad$void print()const;
private:
$\quad$int x;
};
Class dClass: public bClass
{
Public:
$\quad$void setXY(int,int);
$\quad$void print()const;
private:
$\quad$Int y;
};
Which of the following statements correctly redefines the member function print of bClass?
A) void dClass::print() const
{
$\quad$dClass:print();
$\quad$cout << " " << y << endl;
}
B) void dClass::print() const
{
$\quad$cout << x << " " << y << endl;
}
C) void bClass::print() const
{
$\quad$cout << x << " " << y << endl;
}
D) void dClass::print() const
{
$\quad$BClass::print();
$\quad$cout << "y = " << y << endl;
}

Quizplus · Accepted Answer

Option A is incorrect because it recursively calls the print function of dClass and does not print the value of x.
Option B is incorrect because it only prints the value of y, not x.
Option C is incorrect because the derived class dClass has a private data member y, which is inaccessible to bClass and thus cannot be printed in bClass's print function.
Option D is the correct choice as it first calls the print function of the base class bClass through BClass::print(), and then prints the value of y.

Consider the Following Class Definitions: Class BClass { Public \quad

Consider the Following Class Definitions:
Class BClass
{
Public $\quad$