Suppose cType is a class template, and func is a member function of cType.The heading of the function definition of func is: ____. A) template FuncType cType == func(parameters) B) template FuncType cType C) template FuncType cType::func(parameters) D) template FuncType cTypefunc(parameters;

Question

Quizplus · Accepted Answer

Option C is the correct heading for the function definition of func as it includes the template parameter followed by FuncType cType::func(parameters), indicating that func is a member function of the template class cType. Option A is not a valid function header syntax, Option B only declares the function and does not define it, and Option D is missing the scope resolution operator (::) to indicate that func is a member function of the cType class template.

Suppose CType Is a Class Template, and Func Is a Member