What is the output of the following code? queueType<int> queue;
Int x,y;
x = 2;
y = 3;
queue.addQueue(x) ;
queue.addQueue(y) ;
x = queue.front() ;
queue.deleteQueue() ;
queue.addQueue(x + 2) ;
queue.addQueue(x) ;
queue.addQueue(y - 3) ;
y = queue.front() ;
queue.deleteQueue() ;
cout << "x = " << x << endl;
cout << "y = " << y << endl;

Question

What is the output of the following code? queueType<int> queue;
Int x,y;
x = 2;
y = 3;
queue.addQueue(x);
queue.addQueue(y);
x = queue.front();
queue.deleteQueue();
queue.addQueue(x + 2);
queue.addQueue(x);
queue.addQueue(y - 3);
y = queue.front();
queue.deleteQueue();
cout << "x = " << x << endl;
cout << "y = " << y << endl;
A) x = 2
y = 4
B) x = 4
y = 3
C) x = 2
y = 3
D) x = 3
y = 2

Quizplus · Accepted Answer

Initially, x is assigned the value of 2 and y is assigned the value of 3. They are then added to the queue using the addQueue() function.

x is then assigned the value at the front of the queue, which is 2, and is removed from the queue using the deleteQueue() function. The value of x is then updated to x + 2, which is 4, and added back to the queue. The original value of x, which is 2, is then added back to the queue, followed by y - 3, which is 0.

y is then assigned the value at the front of the queue, which is 3, and is removed from the queue using the deleteQueue() function.

Therefore, the final values of x and y are 2 and 3, respectively. Hence, the correct answer is C.

What Is the Output of the Following Code? QueueType<int> Queue;