Let Y = yellow and y = green,and R = round and r = wrinkled.You cross YYRR peas with yyrr peas.All of the F₁ individuals are yellow and round with a genotype of YyRr.You then perform a F₂ cross and get the expected 9:3:3:1 phenotypic ratio.Which of the following is the correct genotypic ratio for yellow,round F₂ individuals? A)1/16 YYRr,2/16 YYRR,2/16 YyRR,4/16 YyRr B)1/16 YyRr,2/16 YYRr,2/16 YyRR,4/16 YYRR C)1/16 YYRR,1/16 YYRr,1/16 YyRR D)1/16 YYRR,2/16 YYRr,2/16 YyRR,4/16 YyRr

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First, let's identify the parental genotypes and the cross performed: YYRR (yellow and round) x yyrr (green and wrinkled) F1: YyRr (yellow and round) F1 x F1: YYRR YyRr YyRr yyrr YyRr YyRR YyRr yyRr YyRr YyRr YyRR yyRr yyrr yyRr yyRr yrrr Expected phenotypic ratio: 9(YR) : 3(Yr) : 3(yR) : 1(yr) Now we need to determine the genotypic ratio of the yellow and round individuals (Y- R-): From the Punnett square above, we can see that the following genotypes result in yellow and round seeds: YYRR (2/16), YyRR (2/16), YYRr (1/16), and YyRr (4/16) Therefore, the genotypic ratio for yellow and round F₂ individuals is: 1/16 YYRR, 2/16 YYRr, 2/16 YyRR, 4/16 YyRr (D)

Let Y = Yellow and Y = Green,and R =