A binomial distribution has 100 trials (n = 100) with a probability of success of 0.25 ($\pi$=0.25). We would like to find the probability of 75 or more successes using the normal distribution to approximate the binomial. Applying the continuity correction factor, what value would be used to calculate a z-score?
A) 74.5
B) 75
C) 75.5
D) 25

Question

Quizplus · Accepted Answer

The continuity correction factor is applied to ensure that the normal distribution is a good approximation for the binomial distribution. The correction factor is 0.5, which is added to the number of successes and subtracted from the number of trials. In this case, the continuity correction factor would be applied as follows:75 + 0.5 = 75.5100 - 75.5 = 24.5Therefore, the value used to calculate the z-score would be 75.5.

A Binomial Distribution Has 100 Trials (N = 100) with a Probability