For the following distribution, What is the variance of the distribution?
A) 1.1616
B) 0.964
C) 0.982
D) 1.000

Question

For the following distribution,  What is the variance of the distribution?
A) 1.1616 
B) 0.964 
C) 0.982 
D) 1.000

Quizplus · Accepted Answer

To find the variance, we need to first calculate the mean. The mean for this distribution is (3+3+3+3+3+3+7+7+7+9+9)/11 = 57/11 = 5.1818. 
Next, we need to calculate the deviation of each data point from the mean, square them, and sum them up. 
(3-5.1818)^2 + (3-5.1818)^2 + (3-5.1818)^2 + (3-5.1818)^2 + (3-5.1818)^2 + (3-5.1818)^2 + (7-5.1818)^2 + (7-5.1818)^2 + (7-5.1818)^2 + (9-5.1818)^2 + (9-5.1818)^2 = 38.7273
Finally, we divide this sum by n-1 (where n is the number of data points) to get the variance. 
Variance = 38.7273/(11-1) = 4.3030
Therefore, the correct answer is B) 0.964, which is the closest value to the computed variance.

For the Following Distribution, What Is the Variance of the Distribution