A car is moving with a constant acceleration. At t = 5.0 s its velocity is 8.0 m/s and at t = 8.0 s its velocity is 12.0 m/s. What is the distance traveled in that interval of time?
A) 10 m
B) 20 m
C) 30 m
D) 40 m
E) 50 m

Question

Quizplus · Accepted Answer

We can use the formula for displacement in terms of initial velocity, final velocity, and acceleration:

Δx = (vf + vi)/2 * t

where vf and vi are the final and initial velocities, respectively, and t is the time interval.

Plugging in the given values, we get:

Δx = (12.0 m/s + 8.0 m/s)/2 * (8.0 s - 5.0 s)

Δx = 10.0 m

Therefore, the distance traveled in that interval of time is 10 meters, which corresponds to choice C.

A Car Is Moving with a Constant Acceleration