A vector is located in the x-y plane. The x- and y-components of this vector are 4.00 m and 3.00 m, respectively. Find the angle that this vector makes with the positive y-axis.
A) 53.1°
B) 36.9°
C) 126.9°
D) 22.4°
E) 48.6°

Question

Quizplus · Accepted Answer

We can use the definition of tangent to find the angle:

$$	an	heta = \frac{	ext{opposite}}{	ext{adjacent}} = \frac{4.00	ext{ m}}{3.00	ext{ m}}$$

Taking the arctangent of both sides of the equation, we get:

$$	heta = \arctan\left(\frac{4.00	ext{ m}}{3.00	ext{ m}}ight) \approx 53.1^\circ$$

Therefore, the answer is choice A) 53.1°.

A Vector Is Located in the X-Y Plane