A bullet is fired with a certain velocity at an angle θ above the horizontal at a location where g = 10.0 m/s². The initial x and y components of its velocity are 86.6 m/s and 50.0 m/s respectively. How long does it take before the bullet gets to the highest point of its trajectory? A) 5.0 seconds B) 10.0 seconds C) 15.0 seconds D) 20.0 seconds E) None of the other choices is correct.

Question

Quizplus · Accepted Answer

To determine the time it takes for the bullet to reach the highest point of its trajectory, we need to first find the vertical component of its velocity at that point, as this will be zero. Using the formula v_fy = v_iy + gt, where v_fy is the final vertical velocity (which is 0 at the highest point), v_iy is the initial vertical velocity (which is 50.0 m/s at the start), g is the acceleration due to gravity (10.0 m/s^2), and t is the time it takes to reach the highest point, we can solve for t:

0 = 50.0 m/s - 10.0 m/s^2 * t
t = 5.0 seconds

Therefore, it takes 5.0 seconds for the bullet to reach the highest point of its trajectory. The answer is (A).

A Bullet Is Fired with a Certain Velocity at an Angle