A person throws a ball horizontally from the top of a building that is 40.0 m high. The initial velocity of the ball is 100 m/s. What is the horizontal distance that the ball travels before hitting the ground?
A) 100 m
B) 286 m
C) 325 m
D) 367 m
E) 572 m

Question

Quizplus · Accepted Answer

The horizontal distance traveled by the ball is given by:```d = v*t```where:* d is the distance traveled (in meters)* v is the initial velocity (in meters per second)* t is the time of flight (in seconds)The time of flight can be found using the following equation:```t = sqrt(2*h/g)```where:* h is the height of the building (in meters)* g is the acceleration due to gravity (in meters per second squared)Substituting the given values into these equations, we get:```t = sqrt(2*40.0 m/9.8 m/s^2) = 4.08 sd = 100 m/s * 4.08 s = 286 m```Therefore, the horizontal distance that the ball travels before hitting the ground is 286 m.

A Person Throws a Ball Horizontally from the Top of a Building