A bullet is fired from ground level with a speed of 150 m/s at an angle 30.0° above the horizontal at a location where g = 10.0 m/s². What is the horizontal component of its velocity after 4 seconds? A) 150 m/s B) 35 m/s C) 130 m/s D) 75.0 m/s E) 37.5 m/s

Question

Quizplus · Accepted Answer

First, we need to find the initial horizontal and vertical components of the bullet's velocity.

The initial horizontal velocity is given by:

v_x = v0cos(theta) = 150*cos(30) = 129.9 m/s

The initial vertical velocity is given by:

v_y = v0sin(theta) = 150*sin(30) = 75.0 m/s

Next, we need to find how far the bullet has traveled horizontally after 4 seconds. We can do this by using the equation:

x = v_x*t = 129.9*4 = 519.6 m

Now, we want to find the horizontal component of the bullet's velocity after 4 seconds, which is simply the initial horizontal velocity:

v_x = 129.9 m/s

Therefore, the best choice is C) 130 m/s.

A Bullet Is Fired from Ground Level with a Speed